旋转图像-数组48-python

python

将原矩阵先水平翻转，再沿主对角线(左上到右下)翻转，就是顺时针翻转90度的效果了。

class Solution:
    def rotate(self, matrix: List[List[int]]) -> None:
        """
        Do not return anything, modify matrix in-place instead.
        """
        n = len(matrix)
        # 水平线翻转
        for i in range(n//2):
            for j in range(n):
                matrix[i][j], matrix[n-i-1][j] = matrix[n-i-1][j], matrix[i][j]
        
        # 对角线翻转
        for i in range(n):
            for j in range(i):
                matrix[i][j], matrix[j][i] = matrix[j][i], matrix[i][j]