shell脚本实现定时开启Apache服务
程序员文章站
2022-07-10 09:22:08
...
- 写shell脚本
#! /bin/bash
case $1 in
start)
systemctl start httpd
if [ $? -eq 0 ]
then
echo "已成功开启httpd服务"
else
echo "开启失败"
fi
;;
stop)
systemctl stop httpd
if [ $? -eq 0 ]
then
echo "已成功关闭httpd服务"
else
echo "关闭失败"
fi
;;
restart)
systemctl restart httpd
if [ $? -eq 0 ]
then
echo "已成功重启httpd服务"
else
echo "重启失败"
fi
;;
*)
echo "没有此项功能,敬请期待"
;;
esac
- 实现定时任务
yum install -y crontabs
systemctl start crond
crontab -e 设置定时任务46 14 * * * . /root/mariadb.sh stop
crontab -l 查看已经设置的定时任务[[email protected] ~]# crontab -l
46 14 * * * . /root/mariadb.sh stop
#! /bin/bash
read -p "请输入您要管理的服务名称:" name
echo "1、开启${name};"
echo "2、重启${name};"
echo "3、关闭${name};"
echo "4、查看${name}状态;"
echo "5、开启定时服务;"
echo "6、退出"
read -p "请选择您要进行的操作:" num
case $num in
1) systemctl start $name
if [ $? -eq 0 ]
then
echo "${name}开启成功!"
else
echo "${name}开启失败!"
fi
;;
2) systemctl restart $name
if [ $? -eq 0 ]
then
echo "${name}重启成功!"
else
echo "${name}重启失败!"
fi
;;
3) systemctl stop $name
if [ $? -eq 0 ]
then
echo "${name}关闭成功!"
else
echo "${name}关闭失败!"
fi
;;
4)
systemctl status $name
;;
5)
read -p "请输入每天自动开启的时间(24小时制):" h_up
read -p "请输入每天自动关闭的时间(24小时制):" h_down
echo "0 ${h_down} * * * systemctl stop $name" > crontab.cron
echo "0 ${h_up} * * * systemctl start $name" >> crontab.cron
crontab crontab.cron
if [ $? -eq 0 ]
then
echo "${name}定时功能开启成功!"
echo "您的设定为每天${h_up}点开启,${h_down}点关闭!"
else
echo "${name}定时功能开启失败!"
fi
;;
6)echo "欢迎下次使用,谢谢!"
;;
*) echo "暂无此功能,正在开发中..."
;;
esac
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