ccf201712-3 crontab

我嬲你麻麻别，我这个小菜鸡是拜倒在这了，我写了感觉得8小时了（一共写3天一天写一会），最后还只得了80，原因我找了，暴力法超时了。这题暴力法不处理英文字符得65，处理大小写得80，然后就我水平有限，分就这样了，改不了了，我发现自己和那些大佬的代码还是差好多，，比如人家用longlong存数，用10^x次方代表月日等，我只会用字符串存，人家用map，我只会数组、。。。
下面是题目和代码，代码要说有优点，就是简单易懂了吧

#include<bits/stdc++.h>
using namespace std;
const string str1[19]={"Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec","Sun","Mon","Tue","Wed","Thu","Fri","Sat"};
const string str2[19]={"jan","feb","mar","apr","may","jun","jul","aug","sep","oct","nov","dec","sun","mon","tue","wed","thu","fri","sat"};
int data[20][6][61]={0};
struct bound{
	int low;
	int high;
}; 
int runnian(int year)
{
	if(year%4==0&&year%100!=0||year%400==0)
	return 1;
	else
	return 0; 
}
vector<string> split(string str,char flag)
{
	vector<string> vs;
	istringstream iss(str);
	while(getline(iss,str,flag))
	vs.push_back(str);
	return vs;
}
int dayue(int mouth)
{
	if(mouth==1||mouth==3||mouth==5||mouth==7||mouth==8||mouth==10||mouth==12)
	return 1;
	else if(mouth==2)
	return -1;
	else
	return 0;
}
int xingqi(int year,int mouth,int day)
{
	int sumday=0;
	int xq=0;
	int syear=0;
	int smouth=1;
	for(syear=1970;syear<year;syear++)
	{
		if(runnian(syear))
		sumday=sumday+366;
		else
		sumday=sumday+365;
	}
	for(smouth=1;smouth<mouth;smouth++)
	{
		if(runnian(syear)&&smouth==2)
		sumday=sumday+29;
		else if((!runnian(syear))&&smouth==2)
		sumday=sumday+28;
		else if(dayue(smouth)==1)
		sumday+=31;
		else
		sumday+=30;
	}
	sumday+=day-1;
	sumday+=4;
	xq=sumday%7;
	return xq;
}
bound _to(string str)
{
	bound bd;
	stringstream s3;
	int pos=str.find('-');
	string s1=str.substr(0,pos);
	string s2=str.substr(pos+1,str.length()-pos-1);
	bd.low=atoi(s1.c_str());
	bd.high=atoi(s2.c_str());
	return bd;
}
int main()
{
	int n;
	cin>>n;
	string start,end;
	cin>>start>>end;
	int s_year,s_mouth,s_day,s_hour,s_min;
	int e_year,e_mouth,e_day,e_hour,e_min;
	s_year=atoi(start.substr(0,4).c_str());
	s_mouth=atoi(start.substr(4,2).c_str());
	s_day=atoi(start.substr(6,2).c_str());
	s_hour=atoi(start.substr(8,2).c_str());
	s_min=atoi(start.substr(10,2).c_str());
	e_year=atoi(end.substr(0,4).c_str());
	e_mouth=atoi(end.substr(4,2).c_str());
	e_day=atoi(end.substr(6,2).c_str());
	e_hour=atoi(end.substr(8,2).c_str());
	e_min=atoi(end.substr(10,2).c_str());	
	string op[21];
	getchar();
	for(int i=0;i<n;i++)
	{	
		getline(cin,op[i]);
		vector<string> vs;
		vs=split(op[i],' ');//vs以空格分段 
		op[i]=vs[5].c_str();//op重写，变为commmand 
		for(int j=0;j<5;j++)
		{
			for(int k=0;k<vs[j].size();k++)
			{
				if(vs[j][k]>='A'&&vs[j][k]<='Z')
				vs[j][k]+=32; 
			}
			for(int k=0;k<19;k++)//英文日期替换整数字符串 
			{
				while(vs[j].find(str2[k])!=vs[j].npos)
				{
					int  pos1=vs[j].find(str2[k]);
					ostringstream os;
					if(k>11){
						os<<k-12;
						vs[j].replace(pos1,3,os.str());
					}
					else{
						os<<k+1;
						vs[j].replace(pos1,3,os.str());
					}	
				}
			}
		//	cout<<vs[j]<<' ';
			if(vs[j]=="*")//*就全赋值 
			{
				switch(j)
				{
					case 0:
						for(int k=0;k<60;k++)
						data[i][j][k]=1;
					break;
					case 1:
						for(int k=0;k<24;k++)
						data[i][j][k]=1;
					break;
					case 2:
						for(int k=1;k<32;k++)
						data[i][j][k]=1;
					break;
					case 3:
						for(int k=1;k<13;k++)
						data[i][j][k]=1;
					break;
					case 4:
						for(int k=0;k<7;k++)
						data[i][j][k]=1;
					break;
					default:
						;
				}
			}
			else
			{
				vector<string> vs1;
				vs1=split(vs[j],',');//vs1以逗号分段 
				for(int k=0;k<vs1.size();k++)
				{
					if(vs1[k].find('-')!=vs1[k].npos)
					{
						bound bd=_to(vs1[k]);
						for(int m=bd.low;m<=bd.high;m++)
						{
							data[i][j][m]=1;
						}
						vs1.erase(vs1.begin()+k);
					}
				}
				for(int k=0;k<vs1.size();k++)
				{
					data[i][j][atoi(vs1[k].c_str())]=1;
				}
			}
			
		}
	}
	int year=s_year;int mouth=s_mouth;int day=s_day;int hour=s_hour;int min=s_min; 
	while(year!=e_year||mouth!=e_mouth||day!=e_day||hour!=e_hour||min!=e_min)//遍历从开始到结束的每一分钟 
	{ 
		int week=xingqi(year,mouth,day);//年月日转星期 
		for(int i=0;i<n;i++)
		{
        	if(data[i][0][min]==1&&data[i][1][hour]==1&&data[i][2][day]==1&&data[i][3][mouth]==1&&data[i][4][week]==1)//0表示分钟，1：小时，2：每月天数，3：月份，4：星期数 
        	{
        		printf("%04d%02d%02d%02d%02d",year,mouth,day,hour,min);
        		cout<<' '<<op[i]<<endl;
			}
		}
		min++;
		if(min>59)
		{
			hour++;
			min=0;
		}
		if(hour>23)
		{
			day++;
			hour=0;
		} 
		if(day>29&&mouth==2&&runnian(year)||day>28&&mouth==2&&!runnian(year)||day>31&&dayue(mouth)||day>30&&(dayue(mouth)==0))
		{
			mouth++;
			day=1;
		}
		if(mouth>12)
		{
			mouth=1;
			year++;
		}
	}
}