ES 查询语法

文章目录

• • 数据类型说明
  • 样例对象

数据类型说明

text keyword text存储的时候会分词，keyword不会

样例对象

@Document(indexName = "bu")
public class Person {

    private @Id
    String id;
    @Field(type = FieldType.Keyword)
    private String name;

    private int age;

    @Field(type = FieldType.Text)
    private String country;

    public String getId() {
        return id;
    }

    public void setId(String id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public int getAge() {
        return age;
    }

    public void setAge(int age) {
        this.age = age;
    }

    public String getCountry() {
        return country;
    }

    public void setCountry(String country) {
        this.country = country;
    }
}

1.精确查询

{
  "from": 0,
  "size": 10,
  "query": {
    "term": {
      "name": {
        "value": "shanghai"
      }
    }
  }
}

java

// An highlighted block
QueryBuilder queryBuilder = QueryBuilders.termQuery("name", "shanghai");
NativeSearchQuery nativeSearchQuery = new NativeSearchQuery(queryBuilder);
List<Person> people = elasticsearchTemplate.queryForList(nativeSearchQuery, Person.class);

2.模糊查找

{
  "query": {
    "match": {
      "country": {
        "query": "china"
      }
    }
  }
}

java

 QueryBuilder queryBuilder = QueryBuilders.matchQuery("country", "china");
 NativeSearchQuery nativeSearchQuery = new NativeSearchQuery(queryBuilder);

3.多词匹配

会匹配多个词语，

操作符	含义
or	只要有一个词匹配就返回
and	两个词都有匹配

{
  "query": {
    "match": {
      "country": {
        "query": "china,japan",
        "operator": "and"
      }
    }
  }
}

java

 QueryBuilder queryBuilder = QueryBuilders.matchQuery("country", "china japan").operator(Operator.AND);

4.多列匹配相同的值

{
  "from": 0,
  "size": 10,
  "query": {
    "multi_match": {
      "fields": [
        "country",
        "name"
      ],
      "query": "shanghai"
    }
  }
}

java

  QueryBuilder queryBuilder = QueryBuilders.multiMatchQuery("china","country","name");

5.must should用法

must 条件必须满足
should 条件可以满足，也可以不满足，会根据shoud里面的匹配情况打分
“minimum_should_match”: 1 就是必须要满足里面的一个值

表达式 country里必须有japan&&id=10||country里必须有japan&&id=11

{
  "from": 0,
  "size": 10,
  "query": {
    "bool": {
      "must": [
        {
          "match": {
            "country": {
              "query": "japan"
            }
          }
        }
      ],
      "minimum_should_match": 1,
      "should": [
        {
          "terms": {
            "id": [
              10,
              11
            ]
          }
        }
      ]
    }
  }
}

java

 BoolQueryBuilder boolQueryBuilder = QueryBuilders.boolQuery().must(QueryBuilders.matchQuery("country", "japan")).should(QueryBuilders.termsQuery("id", Arrays.asList(10, 11)));
        NativeSearchQuery nativeSearchQuery = new NativeSearchQuery(boolQueryBuilder);
        nativeSearchQuery.setMinScore(1);

6.must_not用法

must_not不满足

{
  "from": 0,
  "size": 10,
  "query": {
    "bool": {
      "must": [
        {
          "match": {
            "country": {
              "query": "japan"
            }
          }
        }
      ],
      "must_not": [
        {
          "ids": {
            "values": [10]
          }
        }
      ]
    }
  }
}

java

 BoolQueryBuilder boolQueryBuilder = QueryBuilders.boolQuery().must(QueryBuilders.matchQuery("country", "japan"))
                .mustNot(QueryBuilders.termQuery("id", 10));

7.范围查询排序

{
  "from": 0,
  "size": 10,
  "query": {
    "range": {
      "id": {
        "gte": 10,
        "lt": 16
      }
    }
  },
  "sort": [
    {
      "id.keyword": {
        "order": "asc"
      }
    }
  ]
}

java

 RangeQueryBuilder id = QueryBuilders.rangeQuery("id").gte(10).lt(12);
        NativeSearchQuery nativeSearchQuery = new NativeSearchQuery(id);
        nativeSearchQuery.addSort(new Sort(Sort.Direction.ASC,"id.keyword"));

8.去重

{
  "_source": "name",
  "collapse": {
    "field": "name.keyword"
  }
}

9.group by count

{
  "size": 0,
  "aggs": {
    "count_name": {
      "terms": {
        "field": "name.keyword"
      }
    }
  }
}

10.group by sum