443 String Compression

Given an array of characters, compress it in-place.

The length after compression must always be smaller than or equal to the original array.Every element of the array should be a character (not int) of length 1.

After you are done modifying the input array in-place, return the new length of the array.

Follow up:
Could you solve it using only O(1) extra space?

Example 1:

Input:
["a","a","b","b","c","c","c"]

Output:
Return 6, and the first 6 characters of the input array should be: ["a","2","b","2","c","3"]

Explanation:
"aa" is replaced by "a2". "bb" is replaced by "b2". "ccc" is replaced by "c3".

Example 2:

Input:
["a"]

Output:
Return 1, and the first 1 characters of the input array should be: ["a"]

Explanation:
Nothing is replaced.

Example 3:

Input:
["a","b","b","b","b","b","b","b","b","b","b","b","b"]

Output:
Return 4, and the first 4 characters of the input array should be: ["a","b","1","2"].

Explanation:
Since the character "a" does not repeat, it is not compressed. "bbbbbbbbbbbb" is replaced by "b12".
Notice each digit has it's own entry in the array.

Note:

1. All characters have an ASCII value in [35, 126].
2. 1 <= len(chars) <= 1000.

class Solution {
    public int compress(char[] chars) {
        int index = 0, indexAns = 0;
        while (index < chars.length) {
            char currChar = chars[index];
            int count = 0;
            while (index < chars.length && currChar == chars[index]) {
                index++;
                count++;
            }
            chars[indexAns++] = currChar;
            if (count > 1) {
                for (char c : Integer.toString(count).toCharArray()){
                    chars[indexAns++] = c;
                }
            }
        }
        return indexAns;
    }
}