objdump反汇编用法示例

原文：http://blog.csdn.net/zoomdy/article/details/50563680 

• -d:将代码段反汇编
• -S:将代码段反汇编的同时，将反汇编代码和源代码交替显示，编译时需要给出-g，即需要调试信息。
• -C:将C++符号名逆向解析。
• -l:反汇编代码中插入源代码的文件名和行号。
• -j section:仅反汇编指定的section。可以有多个-j参数来选择多个section。

有代码如下：

class Main
{
    int a;
public:
    Main()
    {
        a = 0;
    }

    int getA(void)
    {
        return this->a;
    }
};

• 
  

$objdump -d a.out # 简单反汇编

08048456 <_ZN4MainC1Ev>:
 8048456:   55                      push   %ebp
 8048457:   89 e5                   mov    %esp,%ebp
 8048459:   8b 45 08                mov    0x8(%ebp),%eax
 804845c:   c7 00 00 00 00 00       movl   $0x0,(%eax)
 8048462:   5d                      pop    %ebp
 8048463:   c3                      ret    

08048464 <_ZN4Main4getAEv>:
 8048464:   55                      push   %ebp
 8048465:   89 e5                   mov    %esp,%ebp
 8048467:   8b 45 08                mov    0x8(%ebp),%eax
 804846a:   8b 00                   mov    (%eax),%eax
 804846c:   5d                      pop    %ebp
 804846d:   c3                      ret    

• 
  

$objdump -S a.out # 反汇编代码中混入对应的源代码

08048456 <_ZN4MainC1Ev>:
class Main
{
    int a;
public:
    Main()
 8048456:   55                      push   %ebp
 8048457:   89 e5                   mov    %esp,%ebp
    {
        a = 0;
 8048459:   8b 45 08                mov    0x8(%ebp),%eax
 804845c:   c7 00 00 00 00 00       movl   $0x0,(%eax)
    }
 8048462:   5d                      pop    %ebp
 8048463:   c3                      ret    

08048464 <_ZN4Main4getAEv>:

    int getA(void)
 8048464:   55                      push   %ebp
 8048465:   89 e5                   mov    %esp,%ebp
    {
        return this->a;
 8048467:   8b 45 08                mov    0x8(%ebp),%eax
 804846a:   8b 00                   mov    (%eax),%eax
    }
 804846c:   5d                      pop    %ebp
 804846d:   c3                      ret    

• 
  

$objdump -C -S a.out # C++符号名逆向解析

08048456 <Main::Main()>:
class Main
{
    int a;
public:
    Main()
 8048456:   55                      push   %ebp
 8048457:   89 e5                   mov    %esp,%ebp
    {
        a = 0;
 8048459:   8b 45 08                mov    0x8(%ebp),%eax
 804845c:   c7 00 00 00 00 00       movl   $0x0,(%eax)
    }
 8048462:   5d                      pop    %ebp
 8048463:   c3                      ret    

08048464 <Main::getA()>:

    int getA(void)
 8048464:   55                      push   %ebp
 8048465:   89 e5                   mov    %esp,%ebp
    {
        return this->a;
 8048467:   8b 45 08                mov    0x8(%ebp),%eax
 804846a:   8b 00                   mov    (%eax),%eax
    }
 804846c:   5d                      pop    %ebp
 804846d:   c3                      ret    

• 
  

objdump -j .text -l -C -S a.out # 打印源文件名和行号

08048456 <Main::Main()>:
_ZN4MainC2Ev():
~/objdump/main.h:5
class Main
{
    int a;
public:
    Main()
 8048456:   55                      push   %ebp
 8048457:   89 e5                   mov    %esp,%ebp
~/objdump/main.h:7
    {
        a = 0;
 8048459:   8b 45 08                mov    0x8(%ebp),%eax
 804845c:   c7 00 00 00 00 00       movl   $0x0,(%eax)
~/objdump/main.h:8
    }
 8048462:   5d                      pop    %ebp
 8048463:   c3                      ret    

08048464 <Main::getA()>:
_ZN4Main4getAEv():
~/objdump/main.h:10

    int getA(void)
 8048464:   55                      push   %ebp
 8048465:   89 e5                   mov    %esp,%ebp
~/objdump/main.h:12
    {
        return this->a;
 8048467:   8b 45 08                mov    0x8(%ebp),%eax
 804846a:   8b 00                   mov    (%eax),%eax
~/objdump/main.h:13
    }
 804846c:   5d                      pop    %ebp
 804846d:   c3                      ret