题目描述:
翻转一个链表
样例
给出一个链表1->2->3->null,这个翻转后的链表为3->2->1->null
挑战
在原地一次翻转完成
题目分析:
在原地一次翻转完成
循环head链表,将链表中的元素从表头依次取出指向新链表即可。
源码:
"""
Definition of ListNode
class ListNode(object):
def __init__(self, val, next=None):
self.val = val
self.next = next
"""
class Solution:
"""
@param head: The first node of the linked list.
@return: You should return the head of the reversed linked list.
Reverse it in-place.
"""
def reverse(self, head):
# write your code here
if head is None: return None
p = head
cur = None
pre = None
while p is not None:
cur = p.next
p.next = pre
pre = p
p = cur
return pre