iOS去除数组中重复数据的几种方法

####第一种：利用NSDictionary的AllKeys（AllValues）方法

NSArray *dataArray = @[@1, @2, @3, @4, @1, @2, @5, @6, @7, @8, @9, @1, @3];
NSMutableDictionary *dic = [[NSMutableDictionary alloc]initWithCapacity:0];
for(NSString *str in dataArray)
{
    [dic setValue:str forKey:str];
}
NSLog(@"DIC %@",[dic allKeys]);
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打印结果：

DIC (
    9,
    5,
    1,
    6,
    2,
    7,
    3,
    8,
    4
)

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####第二种方法：利用NSSet的AllObjects方法

NSArray *dataArray = @[@1, @2, @3, @4, @1, @2, @5, @6, @7, @8, @9, @1, @3];
NSSet *set = [NSSet setWithArray:dataArray];
NSLog(@"SET = %@",[set allObjects]);
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SET = (
    9,
    7,
    5,
    3,
    1,
    8,
    6,
    4,
    2
)

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###第三种方法，利用数组的containsObject来去除 NSArray *dataArray = @[@1, @2, @3, @4, @1, @2, @5, @6, @7, @8, @9, @1, @3]; NSMutableArray *listAry = [[NSMutableArray alloc]init]; for (NSString *str in dataArray) { if (![listAry containsObject:str]) { [listAry addObject:str]; } } NSLog(@"CONTAINS %@",listAry);

打印结果：

CONTAINS (
    1,
    2,
    3,
    4,
    5,
    6,
    7,
    8,
    9
)

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####第四种方法：利用keyValue的方式（自己不是太明白）

 NSArray *dataArray = @[@1, @2, @3, @4, @1, @2, @5, @6, @7, @8, @9, @1, @3];

 NSArray *array1 = [dataArray valueForKeyPath:@"@distinctUnionOfObjects.self"];
 NSLog(@"DISTINC %@",array1);
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打印结果
DISTINC (
    9,
    7,
    5,
    3,
    1,
    8,
    6,
    4,
    2
)

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第五种 : NSOrderedSet去除

NSArray *dataArray = @[@1, @2, @3, @4, @1, @2, @5, @6, @7, @8, @9, @1, @3];
NSOrderedSet *orderSet = [NSOrderedSet orderedSetWithArray:dataArray];
    
NSArray *newArray = orderSet.array;
    
NSLog(@"ORDERSET %@",newArray);

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打印结果
ORDERSET (
    1,
    2,
    3,
    4,
    5,
    6,
    7,
    8,
    9
)

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