Matlab时间

自带函数

startDate = datestr('1900-01-01 00:00:00', 'yyyy-mm-dd HH:MM:SS');
datestr(datenum(startDate) + 61710480/60/24, 'yyyymmdd')

datestr(now, 'yyyymmdd')

自定义函数

function flag = isLeapYear( year )
if (mod(year,4)==0&&mod(year,100)~=0) || mod(year,400)==0
    flag=1;
else
    flag=0;
end

%month(datetime(year, 1, doy))
%day(datetime(year, 1, doy))
function [month,day] = doy2md(doy,year)

dom=[31,28,31,30,31,30,31,31,30,31,30,31];

if isLeapYear(year)
    dom(2)=29;
end

day=doy;
month=1;

while(day>dom(month))
    day=day-dom(month);
    month=month+1;
end

tic, toc

number = 10000;
last_t = 0;
tic;
for i=1:number 
	pause(0.1);
	t=toc;
	
	if t-last_t>=1
		last_t = t;
		hh = floor(t/3600);
		mm = floor(t/60) - 60*hh;
		ss = t - 60*mm - 3600*hh;
		use_time = sprintf("%02d:%02d:%02.3f", hh, mm, ss)

		t = (t/i)*(number-i);
		hh = floor(t/3600);
		mm = floor(t/60) - 60*hh;
		ss = t - 60*mm - 3600*hh;
		left_time = sprintf("%02d:%02d:%02.3f", hh, mm, ss)
	
		clc;
		fprintf('已用时%s，剩余时间%s\n', use_time, left_time );
	end
end

进度条

number = 10000;
for i=1:number
    progress = floor(i/number*30);
    fprintf(['进度：', repmat('█', 1, progress), repmat('□', 1, 30-progress), ' %2.2f%%\n'], i/number*100);
    pause(0.1);
end

时间

julian day得到日期

julian_day = 25854.1424; %(days since 1950-01-01 00:00:00 UTC)
date_obj = datetime(juliandate(1950, 1, 1, 0, 0, 0) + julidan_day, ...
    'ConvertFrom', 'juliandate', ...
    'TimeZone', 'UTC', 'Format', 'yyyy-MM-dd HH:mm:ss.SSS Z');