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LeetCode 525 Contiguous Array (hash)

程序员文章站 2022-03-08 16:44:10
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Given a binary array, find the maximum length of a contiguous subarray with equal number of 0 and 1.

Example 1:

Input: [0,1]
Output: 2
Explanation: [0, 1] is the longest contiguous subarray with equal number of 0 and 1.

 

Example 2:

Input: [0,1,0]
Output: 2
Explanation: [0, 1] (or [1, 0]) is a longest contiguous subarray with equal number of 0 and 1.

Note: The length of the given binary array will not exceed 50,000.

题目链接:https://leetcode.com/problems/contiguous-array/

题目分析:遇0加1,遇1减1,求前缀和,前缀和值相等的一段区间0和1的个数相同,用map记录位置即可

53ms,击败43%

class Solution {
    public int findMaxLength(int[] nums) {
        int n = nums.length;
        if (n == 1) {
            return 0;
        }
        Map<Integer, Integer> mp = new HashMap<>();
        int[] sum = new int[n + 1];
        for (int i = 1; i <= n; i++) {
            sum[i] = sum[i - 1] + (nums[i - 1] == 0 ? 1 : -1) ;
        }
        int ans = 0;
        mp.put(0, 0);
        for (int i = 1; i <= n; i++) {
            if (!mp.containsKey(sum[i])) {
                mp.put(sum[i], i);
            } else {
                ans = Math.max(ans, i - mp.get(sum[i]));
            }
        }
        return ans;
    }
}

未完待续

相关标签: hash