写一个函数返回参数二进制中 1 的个数

#include"stdio.h"
#include"stdlib.h"
#pragma warning(disable:4996)
int my_count(int data)
{
	int i = 0;
	int count = 0;
	for (i = 0; i < 32; i++)
	{
		if ((data>>i)&0x1)
		{
			count++;
		}
	}
	return count;
}

int main()
{
	int value = 0;
	printf("please input a number: ");
	scanf("%d",&value);
	printf("bit counts: %d\n",my_count(value));
	system("pause");
	return 0;
}