简单计算空气质量指数

题目

空气质量指数是描述空气质量状况的无量纲指数，根据污染物的浓度换算得出。编程输入浓度C，输出指数I。其中PM2.5的浓度和级别I列表如下：

Cmin	Cmax	Imin	Imax
0	12.0	0	50
12.1	35.4	51	100
35.5	55.4	101	150
55.5	150.4	151	200
150.5	250.4	201	300
250.5	350.4	301	400
350.5	500.4	401	500

计算公式：

代码

#include <stdio.h>
int main(){
	float c;
	int count_c(float,float,float,float,float);
	printf("请输入PM2.5的浓度C = ");
	scanf("%f",&c);

	if(c>=0&&c<=12.0)	count_c(c,0,12,0,50);
	else if(c>=12.1&&c<=35.4)	count_c(c,12.1,35.4,51,100);
	else if(c>=35.5&&c<=55.4)	count_c(c,35.5,55.4,101,150);
	else if(c>=55.5&&c<=150.4)	count_c(c,55.5,150.4,151,200);
	else if(c>=150.5&&c<=250.4)	count_c(c,150.5,250.4,201,300);
	else if(c>=250.5&&c<=350.4)	count_c(c,250.5,350.4,301,400);
	else if(c>=350.5&&c<=500.4)	count_c(c,350.5,500.4,401,500);
	else 
		printf("浓度爆表！！！！");
	
	return 0;
} 

int count_c(float c,float Cmin,float Cmax,float Imin,float Imax){
	float result;
	result = (Imax-Imin)/(Cmax-Cmin)*(c-Cmin) + Imin;
	printf("当PM2.5的浓度为%6.2f时，对应的空气指数为%6.2f",c,result);
	return 0;
	
}

考试版

#include "stdio.h"
typedef struct{
	float cmin;
	float cmax;
	int lmin;
	int lmax;
}pm;

void main(){
	pm p[7]={0,12.0,0,50,12.1,35.4,51,100,35.5,	55.4,101,150,55.5,150.4,151,200,150.5,250.4,201,300,250.5,350.4,301,400,350.5,500.4,401,500};
	float c,result;
	int i; 
	scanf("%f",&c);
	for(i=0;i<7;i++){
		if(p[i].cmin<=c&&p[i].cmax>=c){
			result = (p[i].lmax-p[i].lmin)/(p[i].cmax-p[i].cmin)*(c-p[i].cmin)+p[i].lmin;
			printf("%6.2f",result);
		}
	}
}