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运算符重载

程序员文章站 2022-05-18 16:34:08
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注意:重载用到ostream时,不能将ostream对象设为const常量,因为此类的成员需要对其他ostream类的方法进行操作。
重载加号:

 Complex operator+(const Complex& A, const Complex& B) {
	 Complex c;
	c.m_x = B.m_x + A.m_x;
	c.m_y = B.m_y + A.m_y;
	return c;

}

<<

ostream& operator<<( ostream& out, const Complex& A) {//重载<<运算符
	
	out <<"[" <<A.m_x << ","<<A.m_y<<"]";
	
	return out;
	
}

前置++和后置++

Complex Complex::operator++() {//前置
	 this->m_x++;
	 this->m_y++;
	 return *this;
 }

 ~~Complex Complex::operator++(int x) {//错误的后置
	 Complex tmp = *this;
	 tmp.m_x++;   		//此处应该是this->m_x++; this->m_y++;
	 tmp.m_y++;
	 return tmp;
 }~~ 
 

```cpp
Complex Complex::operator++(int x) {//正确的后置
	 Complex tmp = *this;
	 m_x++;
	 m_y++;
	 return tmp;
 }
重载+=

```cpp
Complex Complex::operator+=(const Complex& c) {
	 this->m_x += c.m_x;
	 this->m_y += c.m_y;
	 return *this;
 }

测试代码:

#include<iostream>
using namespace std;
#include"Complex.h"
int main() {
	Complex c1(10), c2(20, 10);
	cout << c1 << "+" << c2 << "=" << c1 + c2 << endl;
	cout << (c1 += c2) << endl;
	cout << c1++ << endl;
	cout << ++c1 << endl;
	return 0;
	return 0;
}

错误的运行:
运算符重载
正确的运行结果为:
运算符重载
当我使用错误的重载时,用int型变量进行自增时也会错误。如下:

运算符重载

相关标签: c++ 笔记