php获取当前日期前后几个工作日日期

function getWorkDate($date, $dayNum, $operate=0){
    $alreadyDay = 0;
    $j = 0;
    while($alreadyDay < $dayNum){
        if($operate == 1){
            $date = date('Y-m-d',strtotime($date)+ 24 * 3600);
        }else{
            $date = date('Y-m-d',strtotime($date)- 24 * 3600);
        }
        if($this->isHoliday($date)){
            $j++;
            if($j > 8){ // 限制下最大假期数8天
                break;
            }
            continue;
        }else{
            $alreadyDay++;
        }
    }
    return $date;
}